14v^2-2v=0

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Solution for 14v^2-2v=0 equation:



14v^2-2v=0
a = 14; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·14·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*14}=\frac{0}{28} =0 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*14}=\frac{4}{28} =1/7 $

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